Lemma. Disjointness bounds the rank at an interpolation node [cn-0022]

Status:

Statement. In the polynomial setup [cn-0019], suppose \(U_j\cap V_j=0\). Then

\[\dim E_h(W;t_j)\leq k_h(W)-k_h(V_j).\]

Proof. Let \(\pi _j:W\to W/V_j\) be the quotient map. For any non-node \(t\), its kernel on \(E_h(W;t)\) contains \(E_h(V_j;t)\). The evaluation identity [cn-0020] gives

\[\dim \pi _j(E_h(W;t))\leq k_h(W)-k_h(V_j).\]

Choose a fixed basis of \(\mathcal P_h(W)\), evaluate it at the variable \(\xi \), and project by \(\pi _j\). This is a polynomial matrix. Every minor exceeding the displayed rank bound vanishes at all non-nodes, an infinite set, and is therefore the zero polynomial. The same rank bound holds at \(t_j\). Finally \(E_h(W;t_j)\subseteq U_j\), and \(\pi _j\) is injective on \(U_j\) by disjointness. Thus projection does not reduce its dimension there.

The proof uses vanishing polynomial minors to specialize the rank bound. It does not assume that a generic basis stays independent at a constraint node.

Proof dependencies
Polynomial setup [cn-0019]; Evaluation identity [cn-0020]
Provenance
OpenAI, 23 September 2026 [cn-0042], equation (2.5); reconstructed as a reading account on 9 October 2026. Lean source: NodeRankLoss.