Example. A four-by-four detector you can inspect [cn-0040]

Status: computational-evidence

Statement. For the detector [cn-0032] with \(s=2\), \(n=5\), and nodes \(x_p=p\), the natural half-order matrix [cn-0011] has the following image. Coordinates are ordered as \((a,b)=(0,0),(0,1),(1,0),(1,1)\):

\[\Phi (S)=\frac 1{144}\begin {pmatrix}5&15&15&49\\15&47&49&165\\15&49&47&165\\49&165&165&593\end {pmatrix},\qquad \det \Phi (S)=-\frac 1{1492992}.\]

Its negative determinant shows concretely that an invertible detector image need not be positive semidefinite. The proof needs full rank. The barycentric weights [cn-0030] here are \((1/24,-1/6,1/4,-1/6,1/24)\).

The two-triangle positions [cn-0028] are \((2,1),(3,1),(3,2),(4,5)\). Their evaluation matrix has determinant \(-4\). Substituting these columns and their scalar weights into the factorization [cn-0034] gives exactly the displayed matrix.

The exact script recomputes this example with rational arithmetic and also checks invertibility and the factorization for all 120 linear orders on these five nodes. It records smaller and larger examples in examples.json. The interpolation proof [cn-0029], rather than these finite checks, supplies the assertion for arbitrary distinct nodes and all odd sizes.

Proof dependencies
Half orders [cn-0011]; Evaluation pattern [cn-0028]; Weights [cn-0030]; Detector [cn-0032]; Factorization [cn-0034]
Provenance
Expository organization and source review, 9 October 2026.